Question
In a right angles trainagle, one acute angle is double the other. If the length of its hypotenuse is 20 cm, the find its area?
More Mensuration Questions
- How many bullets can be made out of a lead cylinder 32cm high and 12 cm radius, each bullet being 4 cm in diameter?
- AB is a diameter of a circle with centre O. A tangent is drawn at point A. C is a point on the circle such that BC produced meets the tangent at P. If ∠ AP...
- Number p is 15% more than 150. If k is 15% less than p, then k is equal to:
- A rectangular garden is 50 m long and 35 m wide. Find the cost of fencing it once all around at Rs. 15 per metre.
- The average weight of five friends A, B, C, D and E is (x+8) years while the average weight of C and E is (x-8) kg. If the weight of another person F is al...
- The length of a cuboid is increased by 20%, its breadth is increased by 15% and its height is decreased by 10%. Find the percentage change in its volume.
- The length of a rectangle is 3 metres more than its width. If the perimeter of the rectangle is 70 metres then what is the area (in m2 ) of the rectangle?
- The ratio of length to breadth of a rectangle is 10:13. If the sum of the length and breadth of the rectangle is 92 cm, then find the area (cm2) of the rec...
- In a right-angled triangle PQR, right-angled at Q, the length of the side PR is 17 units, length of the base QR is 8 units, and length of the side PQ is 15...
- Perimeter of a rectangle is 40% more than that of a square of side 25 cm. If the difference between the length and breadth of the rectangle is 12 cm, respe...
Relevant for Exams:
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
Think You're Ready for RBI Grade B?
RBI Grade B 2026 Phase 1 Memory Based Paper
- 200 Questions with Detailed Solutions
- Section-wise Coverage (GA, English, Quant & Reasoning)
Let acute angle be x Other acute angle be 2x Sum of all the angles of triangle = 180° x + 2x + 90 = 180 3x = 90 x = 30 In ∆ABC sin60° = AC/BC 1/2 = BC/20 → BC = 10 cm cos60° = AB/AC →AB/20 √3/2 = AB/20 - AB = 10√3 Area of triangle = 1/2 × base × height = 1/2 × 10√3 × 10 = 50√3 cm²