Question
The curved surface area of a big cylinder is 3696 cm²
and its radius is 21 cm. Another cylinder has the same radius as the big cylinder but its height is half of the big cylinder’s height. The volume of the smaller cylinder is how much percentage of the volume of the big cylinder?Solution
ATQ, Curved surface area = 2 * π * r * h 2 * 22/7 * 21 * h = 3696 (44/7) * 21 * h = 3696 132h = 3696 h = 3696 / 132 h = 28 cm Volume of big cylinder = 22/7 * 21 * 21 * 28 = 22/7 * 441 * 28 = 22/7 * 12348 = 38712 cm³ Height of small cylinder = 28/2 = 14 cm Radius of small cylinder = 21 cm Volume of small cylinder = 22/7 * 21 * 21 * 14 = 22/7 * 441 * 14 = 22/7 * 6174 = 19404 cm³ Required percentage = 19404 / 38712 * 100 = 1/2 * 100 = 50 %
(11/12) × (18/22) × (4/3) + 3 = ?2
- What will come in the place of question mark (?) in the given expression?
32% of 74% of ? = 16% of 37% of 180 30% of 215 + 135% of ? = 469.5
800 + 900 X (3)-2 - ? = 25 X 60 ÷ 2Â
1555.5 + 1000.8 – 1354.3 = ? + 52
- What will come in place of (?), in the given expression.
(4² + 6²) × 2 = ? - 55% of 220 – 15% of 40 = 20% of ?
50 ÷ 2.5 × 64 + ? = 1520
(-251 × 21 × -12) ÷ ? = 158.13