Question
If (3/4)th of a number exceeds
(1/2)th of (x + 8) by 10, then find the value of ‘x’.Solution
ATQ; {(1/2) × (x + 8)} + 10 = (3/4) × x Or, (x + 8)/2 + 10 = (3x/4) Or, (x + 8 + 20)/2 = (3x/4) Or, (x + 28)/2 = (3x/4) Cross-multiplying: 4(x + 28) = 6x 4x + 112 = 6x 112 = 2x So, x = 56
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