Question
The total area of a square and a rectangle is 306 cm².
The breadth of the rectangle is 6 cm more than the length of each side of the square. If the length of the rectangle is 18 cm, then what is the difference between the perimeters of the rectangle and the square?Solution
ATQ,
18(x + 6) + x² = 306 Or, x² + 18x + 108 – 306 = 0 Or, x² + 18x – 198 = 0 Or, x² – 9x + 27x – 198 = 0 Or, x(x – 9) + 22(x – 9) = 0 Or, (x – 9)(x + 22) = 0 Or, x = 9, -22 Since the side cannot be negative, x = 9 Breadth of rectangle = x + 6 = 15 cm Perimeter of rectangle = 2(15 + 18) = 2 × 33 = 66 cm Each side of the square = x = 9 cm Perimeter of square = 4 × 9 = 36 cm Required difference = 66 - 36 = 30 cm
 (108.999)² - (102.001)²=?
30.22% of (61.9 × 5.01) + 69.97 =?Â
2875.45 + ? – 2762.19 = 2145.72 – 1956.63
( 1000)1/3  × 10.11 × 4.97 ÷ 10.32 =? – 15.022
Find the approximate value of Question mark(?) for given equation.Â
104.85% of 479.89 – √2400.91 + (71.92 ÷ 6.03) × 24.85 = ?
...1240.04 – 360.18 + 449.98 ÷ 15.06 = ?
16.02% of (189.15 + 210.87) + 9.02³ - (7.95 of 4.98) = ? of (37.95 - 19.89)
? + 157.99 – 101.01 = 25.01 × 5.98
What will be the approximate value of the following questions.
(1/2 of 959.90 + 69.69% of 359.79) ÷ (√63.94 × 2/5 of 250.14) = ?
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