Question
A rectangle has a perimeter of 160 cm. Its breadth is 40%
less than its length. Calculate the area (in cm²) of a square whose side is 20 cm shorter than the length of the rectangle.Solution
ATQ,
Let the length of the rectangle be '5y' cm
Breadth of the rectangle = (3/5) × 5y = '3y' cm
So, 2 × (5y + 3y) = 160
Or, 8y = 80
Or, 'y' = 10
Length of rectangle = 5 × 10 = 50 cm
Side of the square = 50 - 20 = 30 cm
Therefore, area of the square = (side)² = 30² = 900 cm²
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