Question
Two cylindrical buckets 'A' and 'B' are such that the
radius of bucket 'A' is thrice that of bucket 'B' whereas the height of bucket 'A' is twice that of bucket 'B'. Find the ratio of the volume of bucket 'B' to that of bucket 'A'.Solution
Let the radius and height of bucket 'B' be 'r' unit and 'h' unit respectively.
So, radius of bucket 'A' = '3r' units
And, height of bucket 'A' = '2h' units
Volume of cylinder = π X r 2  X h, where 'r' and 'h' are radius and height, respectively.
Required ratio = (Ï€ X r 2 Â X h) : {Ï€ X (3r)Â 2 Â X 2h} = (r 2 Â X h) :(9r 2 Â X 2h) = 1:18
More Mensuration Questions
(20.98 ÷ 2.91) + (15.12 – 5.96) = ?Â
27.27% of 5501.22 + 12.53% of 158.99 – √ 1599 = ?
47.78% of 499.98 + (19.89 × 7.76) = √? × 49.84
44.89% of 1199.78 + 319.68 = ? × 42.79
?2 = 159.97% of 65.004 + 319.98 ÷ 15.99 - 24
15.232 + 19.98% of 539.99 = ? × 8.99
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(3.21) ? + 37.92 ÷ 1.98 = (5.99 + 3.99) 2
(98.999)2 - (9.9)2 - (14.9)2 = ?
4999.99 ÷ 10.25 + 379.99 - 160.25 = ?Â
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