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Let the radius of the cylinder be '4a' units. So, the height of the cylinder = 4a X (5/4) = '5a' units Radius of the sphere = 4a X 0.75 = '3a' units Volume of the sphere = (4/3) X π X radius3 Volume of the cylinder = π X radius2 X height Therefore, required ratio = ((4/3) X π X radius3) :(π X radius2 X height) = [(4/3) X π X (3a) 3]:[π X (4a) 2 X 5a] = 36:80 = 9:20
3 2 10 ? 17 16
15.975 ×27.825 + (76.01)² + 12.98×18.426 = ?+ (79.09)²
120, 136, 111, 147, ?, 162
80, ?, 240, 80, 20, 4
12 18 31 51 ? 112
3, 8, 27, 124, ?
362 452 550 656 770 892 ?
...76, 80, 89, 105, ?, 166
24, 8, 15, ?, 12, 4
What will come in place of the question mark (?) in the following series?
7, 20, 59, 176, 527, 1580, ?