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Let's assume the height and base of the parallelogram is '14x' cm and '9x' cm, respectively. ATQ; 14x X 9x = 1134 Or, 126x2 = 1134 Or, x2 = 9 Or, x = 3 (since, length cannot be negative therefore, we will take the positive root only) Required difference = 14x - 9x = 5x = 5 X 3 = 15 cm Hence, option a.
What is the nature of the roots of the quadratic equation x² – 5x + 7 = 0 ?
l). 2p² - 10p - 48 = 0
ll). q ² + 5q - 234 = 0
I. 3p² - 14p + 15 = 0
II. 15q² - 34q + 15 = 0
I. 6 y² + 11 y – 7= 0
II. 21 x² + 5 x – 6 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 32x + 252 = 0
Equation 2: y² - 30y + 221 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 97x² - 436x + 339 = 0
Equation 2: 103y² - 460y + 357 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 4x² - 12x + 9 = 0
Equation 2: 2y² + 10y + 12 = 0
I. 8x – 3y = 85
II. 4x – 5y = 67
I. 5x² = 19x – 12
II. 5y² + 11y = 12
Quantity I: A vessel contains a mixture of milk and water in the ratio of 7 : 5. If 9 litre of mixture is sold and replaced by same amount of water then...
