Question
The average of the areas of 2 similar triangles is 706.5
m2 whose perimeters are in the ratio of 6: 11. What is 25% of the difference (in m2) in areas of both triangles?Solution
The ratio of the areas of the similar triangles is (6/11)2 =36/121 Given the average area is 706.5 m², the total area is 1413 m². Let the areas be A₁ = 36x and A2 = 121x. ATQ- 36x+121x =1413 157x =1413 x =1413/157 Solving, x = 9 m². Thus, A₁ = 324 m² and A2 = 1089 m². Difference = 765 m². 30% of the difference =765×30/100= 229.5 m². So, the answer is 229.5 m².
Which country has agreed to host a global peace summit on Ukraine at the request of Ukrainian President Volodymyr Zelenskiy?
Which state won the World Habitat Awards 2023 For Jaga Mission?
Indian Navy Participation Women20@g20 at which of the following city in 27 – 28 Feb 23?
Which platform is supporting Coca Cola India's initial association with ONDC for leveraging data-driven insights and market intelligence?
On which date Good Governance Day is celebrated annually?
Which State has become first in India to have its own Internet Service K - Fon?
__________ and Federal Bank will partner with association of microfinance institutions Sa-Dhan and Delhi-based fintech solutions provider NextGen to pro...
Which of the following is a Jhangora crop season?
In which Indian state is Makar Sankranti known as 'Magha Saaji'?
What is India's projected position in the global e-commerce market by 2030?
Relevant for Exams:
