Question
The average of the areas of 2 similar triangles is 706.5
m2 whose perimeters are in the ratio of 6: 11. What is 25% of the difference (in m2) in areas of both triangles?Solution
The ratio of the areas of the similar triangles is (6/11)2 =36/121 Given the average area is 706.5 m², the total area is 1413 m². Let the areas be A₁ = 36x and A2 = 121x. ATQ- 36x+121x =1413 157x =1413 x =1413/157 Solving, x = 9 m². Thus, A₁ = 324 m² and A2 = 1089 m². Difference = 765 m². 30% of the difference =765×30/100= 229.5 m². So, the answer is 229.5 m².
The material which can be deformed permanently by heat and pressure is called a:
When a passenger in a moving bus is suddenly thrown forward when the bus stops, this is explained by:
A solid non-conducting sphere of radius R carries a uniform volume charge density ρ. What is the ratio of electric field at r = R (surface) to that at ...
Figure-out the case from the following in which the rope will break if an animal of mass 30 kg climbs on a rope, which can stand a maximum tension of 5...
Why do brads not have respiratory trouble at the time of flying at high all?
A projectile is launched at an angle of 30° with the horizontal and remains in the air for 5 seconds. What is the range of the projectile? (Take g = 10...
Charges +q and –q are placed at (–d, 0) and (+d, 0). A third charge Q is placed at (0, x). For what value of x will the force on Q be maximum?
A brass boiler has a base area of 0.2 m2 and thickness 1.0 cm. It boils water at the rate of 6.0 kg/min when placed on a stove. Calculate th...
What is the magnitude of magnetic force per unit length on a wire carrying a current of 10 A and making an angle of 30° with the direction of a unif...
Relevant for Exams:
