Question
The average of the areas of 2 similar triangles is 706.5
m2 whose perimeters are in the ratio of 6: 11. What is 25% of the difference (in m2) in areas of both triangles?Solution
The ratio of the areas of the similar triangles is (6/11)2 =36/121 Given the average area is 706.5 m², the total area is 1413 m². Let the areas be A₁ = 36x and A2 = 121x. ATQ- 36x+121x =1413 157x =1413 x =1413/157 Solving, x = 9 m². Thus, A₁ = 324 m² and A2 = 1089 m². Difference = 765 m². 30% of the difference =765×30/100= 229.5 m². So, the answer is 229.5 m².
More Mensuration Questions
25, 32, 47, 77, 126, 198
- Find the wrong number in the given number series.
350, 289, 238, 197, 158, 145 15, 34, 13, 32, 11, 28
Find the wrong number in the given number series.
24, 120, 721, 5040, 40320, 362880
72, 80, 89, 153, 180, 394
360, 322, 286, 248, 220, 190
3 5 9 17 32 65
...Find the wrong number in the given number series.
65, 91, 127, 163, 217, 271
1, 1, 3, 15, 105, 942
120, 139, 196, 291, 420, 595
Relevant for Exams:
