Question
Steel is used to make a hemispherical bowl that is 0.4
cm thick. The bowl's inner radius is 7 cm. Find the bowl's outside curved surface.Solution
Thickness =R-r 0.4cm =R-7 R=7.4cm. The curved surface of the hemispherical bowl =2 πR2 =2×22/7×7.4×7.4 =344.20cm2
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