Question
If the length of certain rectangle is decreased by 4 cm
and breadth is increased by 2 cm, it would result in a square of the same area. What is the perimeter of the original rectangle?Solution
Let, L = length  B = breadth of rectangle ATQ, (L – 4) = (B + 2)  L – B = 6 .........(1) Also, LB = (L – 4) (B + 2) LB = LB – 4B + 2L – 8  4B – 2L = – 8 ........(2) After solving (i) and (ii) B=2, L=8 L + B = 10 Now perimeter - Þ 2 (L + B) = 2(10) = 20 cm
20.132 ÷ 62.5% of 11.16 = ? + 5109.21
7.992 + (4.01 × 3.98) + ? = 224.03
88% of 1620 + 29² = ? + 1482 ÷ 18
35.1% of 1599 = ?–(449.96 ÷ 6.12) × 2
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
 (3/5) of 3025 + (18² + 12²) = ? + 22.22% of 1125
((341.789)1/3 × (0.0049)1/2)× 429.798/6.88 =?
40.02% of 1220.05 = ?2 + 29.09 × 7.99
15.35 x (58.25 + 63.98) = ? + 1029.78
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