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Given - πr2 = 154m2 R = 154×7/22 = 7m 1/3× πr2h= 1232 m3 h= 1232×3/154 h= 24m now – l2 = r2+h2 =49+576 =625 l = 25m Area of the canvas required to build the tent = πrl Which will equal to the area of the rectangular canvas. 22/7×7×25 = 11×length of the canvas length of the canvas =50m
25 13.5 12.5 20.75 39.5 ? 302.25
...There are three series given below which are following with the same pattern.
Series I: 21, 44, 135, 544, 2725
Series II: 14, B, C, D, E
22 23 32 57 106 ?
If 10 9 38 x 5428
Then, 2x² + 1 = ?
...122, 116, 125, 119, 128, ?
4 14 130 512 �...
2187, 1458, 972, ?, 432, 288
28 34 63 ? 769 3847
...5 3 3 5 15 ?
22 44 176 1078 8448
...