There's a cone of height 12cm out of which a smaller cone with the same vertex and vertical axis is cut out. What is the ratio of the volume of the larger cone to the remaining part of the cone if the height of the smaller cone is 9 centimeters?
Ratio of height = h1/h2 = 9/12 = ¾ Therefore, Ratio of volumes = (3)3 / (4)3 = 64/27 Hence, the volume of the smaller cone = 27x And the volume of larger cone = 64x Hence the required difference = 64x-27x = 37x Required ratio = 64x/37x = 64:37
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