Question
A cone is cut parallel to its base in 3 parts in such a
way that the height of each part is same. Find the ratio of volume of these parts?Solution
Volume of cone ABC = 1/3 π(r1)2 h ............(1) Volume of Frustrum BCED = 1/3 π(2r1)2 2h - 1/3 π(r1)2h = 7/3 π(r1)2 h ............(2) Volume of Frustrum DEGF = 1/3 π(3r1)2 3h - 1/3 π(2r1)2 2h = 19/3 π(r1)2 h ............(3) Now, ratio = 1/3 π(r1)2 h: 7/3 π(r1)2 h: 19/3 π(r1)2 h = 1:7:19 
√10000 × √8100 - (50)² = √(?) + (80)²
√0.49 + √6.25 + √1.44 + √1.21 =? % of 125
The income of a person is Rs.15000 and his expenditure is Rs.12000. In the next year his income and expenditure is increased by 8% and 13% respectively....
(21 X 5) + ? = (480 - 120) ÷ 3
20.05% of 220.05 – 15.15% of 99.99 × 2.02 = ?
1200% of 18 + √1600 + 62 = ?2 + (90 of 0.4)
139 + 323 – √169 + ? = 450
25.6% of 250 + √? = 119    Â
- 55% of 220 – 15% of 40 = 20% of ?
(560 ÷ 32) × (720 ÷ 48) = ?