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Let the length of the edges of the two cubes be ‘a’ cm and ‘b’ cm, respectively According to the question, 6a2 + 6b2 = 1926 Or, a2 + b2 = 1926/6 = 321 And, ab = 136 Using the formula, x2 + y2 = (x – y)2 + 2xy 321 = (a – b)2 + 2 × 136 Or, (a – b)2 = 321 – 272 Or, (a – b)2 = 49 Or, a – b = ±7 So desired difference = 7 cm
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