Question
A rectangular piece of copper foil of length 49 cm and
area 1078 cm2 is folded along its width to form a cylinder such that there is only one layer of copper foil on any part of the cylinder. What is the volume (in cm3) of the cylinder so formed?Solution
Width of the rectangular piece of copper foil = 1078/49 = 22 cm Since the foil is folded along its width to form a cylinder without any double layer, circumference of the cylinder formed = width of the rectangular foil Also, height of the cylinder so formed = length of the rectangular copper foil So, 2 × π × radius = 22 Radius of cylinder = 22 ÷ (2 × 22/7) = (22/44) × 7 = 3.5 cm So, volume of the cylinder so formed = π × (radius)2 × height = (22/7) × 3.5 × 3.5 × 49 = 1886.5 cm³
2.4 of 7.2 of 1/57.6 of 4200 = ?
245 + (45 ÷ 3 + 5) × 6 - 125 = ?
- 45% of 160 – 25% of 80 = 20% of ?
2*1/3 + 22*1/3 + 222*1/3 + 2222*1/2 + 22222*1/2 = ?
44.99% of 499.98 × (3.30/7.40)% of 1399.97 + 10.02 = ?
242 + 18 × 8 – ? = 356
- What will come in place of (?), in the given expression.
125% of 96 + 33% of 300 = ? (21 × 51 + 81)/(9 × 14 - 30) = ?
(2 ÷ 3) × (4 ÷ 12) × (? ÷ 10) × 45 × (1 ÷ 5) = (? ÷ 6) + (2 ÷ 5)
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