Question
The area of a square is 225 cm2 which is 125
cm2 less than that of a rectangle. Find the perimeter of the rectangle if the length of the rectangle is 10 cm more than the length of each side of the square.Solution
Area of the square = 225 cm2 Length of each side of the square = √225 = 15 cm Area of the rectangle = 225 + 125 = 350 cm2 Length of the rectangle = 10 + 15 = 25 cm So, area of rectangle = length × breadth = 25 × breadth = 350 cm2 So, breadth of the rectangle = 350/25 = 14 cm Therefore, perimeter of the rectangle = 2 × (length +breadth) = 2 × (14 + 25) = 78 cm
2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 19Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 70...
6000 3002 1503 ? 378.75 191.375 97.6875
...If  204    196       223   x  284
Then, what is the average of the numbers of the above series?
...8   24    12    ?   18     54
3 ? 7 16 71 346
...104   106   110   113   ?   126
12, 18, 28, 42, 52, ?
18Â Â Â Â Â Â Â Â Â Â Â Â 29 Â Â Â Â Â Â Â Â Â Â Â Â Â Â 51 Â Â Â Â Â Â Â Â 84 Â Â Â Â Â Â Â Â 128 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 182
5, 8, 17, ?, 37, 48
(32.03 + 111.98) ÷ 18.211 = 89.9 – 20.23% of ?
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