Question
The area of a square is 100 cm2 which is 160
cm2 less than that of a rectangle. Find the perimeter of the rectangle if the length of the rectangle is 10 cm more than the length of each side of the square.Solution
Area of the square = 100 cm2 Length of each side of the square = √100 = 10 cm Area of the rectangle = 100 + 160 = 260 cm2 Length of the rectangle = 10 + 10 = 20 cm So, area of rectangle = length × breadth = 20 × breadth = 260 cm2 So, breadth of the rectangle = 260/20 = 13 cm Therefore, perimeter of the rectangle = 2 × (length +breadth) = 2 × (13 + 20) = 66 cm
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