Question
There is a rectangular paper, whose length and breadth
are in the ratio 7:8, respectively and it has a perimeter of 60 metres. If a triangular piece with height of 11 metres and base of 10 metres is cut out from the given paper then find the area (in m2) of the remaining paper.Solution
Let the length and breadth of the rectangular be ‘7x’ metres and ‘8x’ metres, respectively Then, perimeter of the paper = 2 × (length + breadth) = 2 × (7x + 8x) = 30 x metres So, 30x = 60 So, x = (60/30) = 2 So, area of the entire paper = length × breadth = (7 × 2) × (8 × 2) = 14 × 16 = 224 m2 Area of the triangular piece = (1/2) × base × height = (1/2) × 11 × 10 = 55 m2 So, area of the remaining paper = 224 – 55 = 169 m2
If a + b + c = 14 and ab + bc + ca = 60, then find the value of a² + b² + c².
Which of the following options gives the value of 2999² – 999²?
11, 18, 27, 38, 54, 66
If x + y + z = 9 and xy + yz + zx = 26, find the value of x³ + y³ + z³ − 3xyz.
If 3x + (1/3x) = 9 then find 27x³ + (1/27x³ ) = ?
125 sweets were distributed equally among children in such a way that the number of sweets received by each child is 20% of the total number of children...
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If n = 6 + √13, then find the value of (n + 1/n)².
If (x + y) = 35, then find the value of (x - 10)6 + (y - 25)6.
