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Area of the track = length of track x breadth of track = 30 x breadth of track = 4500 So, breadth of track = 4500 ÷ 30 = 150 So, perimeter of the track = (30 + 150) x 2 = 360 metres So, speed of the car = (360/20) = 18 m/s Relative speed of the car with respect to the person = 18 + 5 = 23 m/s So, distance between the car and the person, 3 seconds before they cross each other = 23 x 3 = 69 metres
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