A well with 20 m inside diameter is dug 10 m deep. Soil taken out of it has been evenly spread all around it to a width of 30 m to form an embankment. Find the height of the embankment.

Solution

Volume of the soil dug out = `Pi` r²h ⟹( [if gte msEquation 12]>( 22 7 [if !msEquation]--> `(22)/(7)` [endif]-->x 10 x 10 x 10) = 3,142.85m³. Area of embankment = Area of embankment with well - Area of well = ( x 40 x 40) - ( x 10 x 10 ) = 4,714 m² Height of embankment = `(Volume)/(Area)` [if gte msEquation 12]> Volume Area [if !msEquation]-->[endif]-->= `(3142.85)/(4714.3)` [if gte msEquation 12]> 3142.85 4714.3 [if !msEquation]-->[endif]-->= `(2)/(3)` [if gte msEquation 12]> 2 3 [if !msEquation]-->[endif]-->m.