Question
On a rectangular wall of length 25 metres and height 20
metres, there is a window in the shape of triangle surmounted on a square. If the base of triangle and square overlap and length of each side of the square is 7 metres and length of altitude of the triangle is 4 metres, then excluding the window, what is the surface area of the wall?Solution
Surface area of the entire wall = length × height = 25 × 20 = 500 m2 Surface area of the window = sum of surface area of the square part + surface area of the triangular part => 72 + (1/2) × 7 × 4 => 49 + 14 = 63 m2 Required surface area = 500 – 63 = 437 m2
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