Question
On a rectangular wall of length 24 metres and height 19
metres, there is a window in the shape of triangle surmounted on a square. If the base of triangle and square overlap and length of each side of the square is 6 metres and length of altitude of the triangle is 4 metres, then excluding the window, what is the surface area of the wall?Solution
Surface area of the entire wall = length × height = 24 × 19 = 456 m2 Surface area of the window = sum of surface area of the square part + surface area of the triangular part => 62 + (1/2) × 6 × 4 => 36 + 12 = 48 m2 Required surface area = 456 – 48 = 408 m2
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