The perimeters of two similar triangles, ∆ PQR and ∆ XYZ are 48 cm and 24 cm respectively. If XY = 12 cm. then PQ is:
When two triangles are similar to each other, the ratio of their corresponding sides is equal to the ratio of their respective other sides, medians, and perimeters. ⇒ Perimeter of ΔPQR/Perimeter of ΔXYZ = PQ/XY => 48/24 = PQ/12 ⇒ PQ/12 = 2 ⇒ PQ = 24 m ∴ The length of side PQ = 24 cm
I. 2x² - 15x + 13 = 0
II. 3y² - 6y + 3 = 0
I. 6x2- 41x+13=0
II. 2y2- 19y+42=0
I. 2p2 - 3p – 2 = 0 II. 2q2 - 11q + 15 = 0
I. √(17x) + √51 = 0
II. √(4y) + 3 = 0
I. 6y2- 17y + 12 = 0
II. 15x2- 38x + 24 = 0
I. 2x2 – 5x - 12 = 0
II. y2 – 11y + 30 = 0
I. x² + 11x + 24 = 0
II. y² + 17y + 72 = 0
I. 27x6-152x3+125=0
II. 216y6 -91y3+8=0
I. (4x-5)3 + 1/(4x-5)3 = 2
II. 2[(y+1/y)2- 2]- 9(y+1/y)= -14
I. 35x² + 83x + 36 = 0
II. 42y² + 53y + 15 = 0