Question
If the two adjacent sides of a rectangle are x cm and x
– 10 cm and its perimeter is 116 cm then find its area?Solution
Let the length and breadth of rectangle = x and x – 10 cm Perimeter of rectangle = 2 x [Length + Breadth] According to the question Perimeter of rectangle = 116 cm ⇒ 2 x [Length + Breadth] = 116 ⇒ x + x – 10 = 58 ⇒ Length = x = 34 cm Breadth = (x – 10) = 24 cm Area of rectangle = Length x Breadth Area of rectangle = 34 x 24 Area of rectangle = 816 cm²
- Determine the final value of this expression:
(1/5) of {5⁴ - 24 × 14 + 12 × 18 - 10.5 of 10²} 3% of 842 ÷ 2% of 421 = ?
√225 + 27 × 10 + ? = 320
- Determine the value of ‘p’ if p = √529 + √1444
45 % of 180 + √144 * 8 = ?2 + 70 % of 80
Determine the value of 'p' in following expression:
720 ÷ 9 + 640 ÷ 16 - p = √121 X 5 + 6²- 7?2 = √20.25 × 10 + √16 + 32
- What will come in place of the question mark (?) in the following questions?
(2⁴ + 6²) ÷ 2 = ? 18(1/3) + 9(2/3) – 10(1/3) = 1(2/3) + ?