Question
The lateral surface area of a cube is 400 cm2
. The length of a cuboid is 15% more than the side of the cube. The breadth of the cuboid is 6 cm less than its length and 20% less than its height. Find the total surface area of the cuboid.Solution
Let the length of the cube be ‘a’ cm According to the question, 4a2 = 400 => a2 = 100 => a = 10 Therefore, length of the cuboid = l = 1.15 × 10 = 11.5 cm Breadth of the cuboid = b = 11.5 – 6 = 5.5 cm Height of the cuboid = h = 5.5/0.8 = 6.875 cm Therefore, total surface area of the cuboid = 2(lb + bh + lh) = 2 × {(11.5 × 5.5) + (5.5 × 6.875) + (11.5 × 6.875)} = 360.25 cm2
In the question assuming the given statements to be true, find which of the conclusion(s) among given three conclusions is/are definitely follows and t...
Statement: P ≤ W < O = D ≥ G > T
Conclusions:
I. P ≤ T
II. W < D
Statement: X≤Y<W =Z ≤U<S;S>T ≥V
I. Z≥T
II. Z > X
Statements : C © S * R, U % R $ ZÂ
Conclusions :Â
I. Z $ CÂ
II. U % SÂ
III. U © C
Statements: N = Q < X ≤ L, L > T = G ≥ E
Conclusions:
I. L ≥ Q
II. G > X
III. L > N
Statements: U > H ≥ W; S > T ≥ B; S < H; C ≤ D = U
Conclusions:
I. D > B
II. T < U
III. W ≤ D
Statements: B < C ≥ D; T < G ≥ E; E < C
Conclusions:
I. T < C
II. C > G
III. E < D
In this question, the relation between various elements is shown in the statement. After the statement, two conclusions are given, select a suitable op...
Statements: P # Q @ R & S $ T # W % I, K $ S @ L
Conclusions: I. K # I II. P & T
...Statements : Z < S < W < D; E ≤ C ≤ Y < D; U < T < S ≤ V
Conclusions :
I. V > Z
II. C < U
III. V > E
