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      Question

      The perimeter of a square field is 16 cm more than the

      perimeter of a rectangle. The length of the rectangle is 54 cm which is 225% of its width. If a street of width 10 cm surrounds from outside the square, then find the total cost of constructing the street at the rate of Rs. 25 per sq. cm?
      A Rs. 35,200 Correct Answer Incorrect Answer
      B Rs. 45,000 Correct Answer Incorrect Answer
      C Rs. 34,000 Correct Answer Incorrect Answer
      D Rs. 53,680 Correct Answer Incorrect Answer
      E Rs. 53,000 Correct Answer Incorrect Answer

      Solution

      Let the width of the rectangle = x cm Then, 225% of x = 54 x = 54 × 100/225 = 24 cm Perimeter of the rectangle = 2(length + width) = 2 × (54 + 24) = 156 cm Perimeter of the square = (156 + 16) = 172 cm The sides of the square = 172/4 = 43 cm The area of the square field without street = (43)2 sq. cm = 1849 sq. cm The area of the square field with street = (43 + 20)2 sq. cm = 3969 sq. cm The area of the street = 3969 – 1849 = 2120 sq. cm The total cost of constructing the street = 2120 × 25 = Rs. 53,000

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