Question
A company has three departments: A, B, and C. The total
monthly salary expenditure is ₹1,200,000. Department A spends 50% of the total salary, Department B spends 30%, and Department C spends the rest. If Department A has 20 employees, Department B has 15 employees, and Department C has 10 employees, what is the average salary of an employee in each department?Solution
Department A's expenditure = 50% of 1,200,000 = ₹600,000. Average salary in A = 600,000 / 20 = ₹30,000. Department B's expenditure = 30% of 1,200,000 = ₹360,000. Average salary in B = 360,000 / 15 = ₹24,000. Department C's expenditure = 20% of 1,200,000 = ₹240,000. Average salary in C = 240,000 / 10 = ₹24,000. Correct answer: C) ₹30,000 in A, ₹24,000 in B, ₹24,000 in C
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 24x + 143 = 0
Equation 2: y² - 20y + 96 = 0
l. 3x2 + 17x + 24 = 0
II. 2y2 + 15y + 27 = 0
I. x2 – 3(x + 5) = -11
II. y2 – 4(y + 2) = -2y
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0
If α, β are the roots of the equation x² – px + q = 0, then the value of α2+β2+2αβ is
...I. 2y2 + 11y + 15 = 0
II. 3x2 + 4x - 4= 0
I. 3p² + 13p + 14 = 0
II. 8q² + 26q + 21 = 0
- Suppose both the roots of q² + kq + 49 = 0 are real and equal, then determine the value of 'k'.
I. x2 – 18x + 81 = 0
II. y2 – 3y - 28 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 34x + 285 = 0
Equation 2: y² - 26y + 165 = 0
