From 110m high towers, the angle of depression of a car is 45°. Then how far the car is from the tower?
From 110m high towers, the angle of depression of a car is 45° AB is the height of the tower which is 110 m. C is the point at which the car is standing. InΔ ABC Tan 45° = AB/BC 1 = AB/BC AB = BC = 110m Distance between Tower and car is 110m.
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