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In ∆ABP, tan θ = x/40 ……………. (i) In ∆ BCQ, tan (90 – θ) = 2x/40 Cot θ = 2x/40 ………. (ii) Multiplying both the equations, Tan θ. cot θ = x/40 × 2x/40 1 = x²/800 x² = 800 x = 20√2 Height of the big pillar = 2 × 20√2 = 40√2 m
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