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ATQ, Let HCF of two numbers be ‘x’ So, LCM of two numbers = 12 × x = 12x Or, x × 12x = 25920 Or, 12x² = 25920 Or, x² = 2160 Or, x = √2160 = 46.48 (Approx 46) LCM of two numbers = 46 × 12 = 552 Let two numbers be ‘46a’ and ‘46b’, where ‘a’ and ‘b’ are co-prime numbers. So, 46ab = 552 Or, a × b = 12 So, when a = 1 and b = 12, then difference will be maximum Desired difference = 46 × 12 – 46 × 1 = 506
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