Question
Two numbers are in the ratio 3:7. The product of their
H.C.F. and L.C.M. is 2541. The sum of the numbers is:Solution
Let the numbers be 3x and 7x respectively. First number × second number = HCF × LCM => 3x × 7x = 2541 => x2 = [2541/(3×7)] = 121 => x = √121 = 11 Sum of the numbers = 3x + 7x = 10x = 11 × 10 = 110
More HCF and LCM Questions
654.056 + 28.9015 × 44.851 – 43.129 =?
If √3n 729, then the value of n is equal to:
15(2/9) + 11(2/9) + 17(1/9) + 13(4/9) = ?
(√ 1444 ÷ 5) × 3.25 = ?
What will come in place of (?) in the given expression.
(15) ² - (13) ² = ?808 ÷ (128)1/7 + 482 = 4 × ? + 846
(25 + 12) x 6 + 34 = ? + 18
522 + 160% of 80 - 130 = ? X 13Â
(5/8) x 320 + 100 = ?% of 200 + 90
Evaluate: 96 ÷ 6 × (3 + 5) − 7²
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