Question
Two numbers are in the ratio 3:7. The product of their
H.C.F. and L.C.M. is 2541. The sum of the numbers is:Solution
Let the numbers be 3x and 7x respectively. First number × second number = HCF × LCM => 3x × 7x = 2541 => x2 = [2541/(3×7)] = 121 => x = √121 = 11 Sum of the numbers = 3x + 7x = 10x = 11 × 10 = 110
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