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    Question

    The smallest number which when divided by 27 and 36

    leaves remainder 12 and 21 respectively is:
    A 75 Correct Answer Incorrect Answer
    B 82 Correct Answer Incorrect Answer
    C 61 Correct Answer Incorrect Answer
    D 93 Correct Answer Incorrect Answer

    Solution

    The number = LCM (27, 36) тАУ k, (where k = 27 тАУ 12 = 36 тАУ 21 = 15) LCM of 27 and 38 = 108 Subtract the common difference from 108, Required number will be = 108 - 15 = 93

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