Question
The smallest number which when divided by 27 and 36
leaves remainder 12 and 21 respectively is:Solution
The number = LCM (27, 36) – k, (where k = 27 – 12 = 36 – 21 = 15) LCM of 27 and 38 = 108 Subtract the common difference from 108, Required number will be = 108 - 15 = 93
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