Question
In ΔABC, PQ is parallel to BC If AP: PB= 3:2 and AQ= 6
cm, AC is equal to?Solution
As in ΔABC, PQ is parallel to BC then ΔAPQ is similiar to ΔABC, So by similarity, AP/AB = AQ/AC So 3/(3 + 2) = 6/AC or 3/5 = 6/AC or AC = 10 cm
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