Question
Find the area of triangle having sides 20 m, 21 m, and
29 m.Solution
As sides 20, 21 & 29 is a Pythagoras triplet means 202 + 212 = 292 ; this is a right angle triangle. So area of this triangle = 1/2 × base × height = (1/2) × 20 × 21 = 210 cm 2
(168 ÷ 12 + 19 × 64)/(22+1) = ?
(√ 1444 ÷ 5) × 3.25 = ?
(13)2 + 6 × (19)2 – 312 × 4 = ?
What will come in the place of question mark (?) in the given expression?
224 ÷ 8 + 480 ÷ 15 = ? ÷ 2 – 270 ÷ 18
? ÷ 8 = 2048 ÷ 64
72 x 60 x 22 x 32 =?
(320 + 342 + 530 + 915) ÷ (20 + 22 – x + 18) = 43, then the value of x is:
(5/8) x 320 + 100 = ?% of 200 + 90
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}