Question
Length of a chord in a circle of radius 'r' cm, is 40 cm
and distance between chord and centre of the circle is 21 cm. Find the value of (2r + 1).Solution

AB is the chord of circle.
Perpendicular line joining the centre of circle and chord, bisects the chord.
i.e. AC = BC = (40/2) = 20 cm
By Pythagoras theorem,
OA 2 = OC 2 + AC 2
Or, r 2 = 21 2 + 20 2
Or, r 2 = 441 + 400
Or, r 2 = 841
So, 'r' = 29
But length cannot be negative. So, 'r' = 29
Required value = 2 X 29 + 1 = 59
Select the option that is related to the third number in the same way as the second number is related to the first number.
55 : 3136 :: 48 : ?8, 20, 48, 108, 232, 482
- Choose the pair of words which expresses the same relationship as
6 : 37 Select the option that is related to the third word in the same way as the second word is related to the first word.
Expand: Enlarge :: Condense: ?
From among the given alternatives select the one in which the set of numbers is most likely the set of numbers given in the question.
Given se...
Awful : Terrible :: Descent : ?
Statements: L > J > W = Z < H < V ≤ U; V > P > H ≥ C; I = V ≤ E
Conclusions:
I. I > W
II. U > Z
III. I ≤ E
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In the following question, select the related word pair from the given alternatives.Â
Map: Geography
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