Question
The perimeter of a rectangle is 60 meters. If the length
of the rectangle is twice the width, find the area of the rectangle.Solution
Let the width of the rectangle be x meters. Length = 2x meters. Perimeter of rectangle = 2(length + width) = 60 meters. 2(2x + x) = 60 6x = 60 x = 10. So, the width is 10 meters, and the length is 20 meters. Area = length × width = 20 × 10 = 200 sq. meters. Answer: a) 200 sq. meters
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