Question
In the given figure, radius of a circle is 14 √2
In the given figure, radius of a circle is 14 √2
cm. PQRS is a square. EFGH, ABCD, WXYZ and LMNO are four identical squares. What is the total area (in cm2 ) of all the small squares?
Radius → 14√2, diameter = 28√2 Side = diagonal / √2 = 28√2 / √2 = 28 Side of square = 28 JO = 14 and JK = side of square small s Ok = 14 + 5 Kr = s/2 , and OX = 14√2 PGT ∆ OKx (S/2)2 + (14 + S)2 = (14√2)2 S2 / 4 + 196 + S2 + 285 = 392 S = 5.6 a2 = (5.6)2 = 31.36 = 31.36 × 4 = 125.44 cm2More Geometry Questions
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