In the given figure, ABC is a right angled triangle. ∠ ABC = 90 0and ∠ ACB = 60 0. If the radius of the smaller circle is 2 cm, then what is the radius (in cm) of the larger circle?
IN ∆ PQC, PC = 2PQ PQ is radius of Bigger circle PC = 2 × R PC = 2R PC = PO +OC PC = R + 2 + 4 2R = R + 2 + 4 R = 6
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