Question
Find out the circumference of a sector whose radius is 7
cm and it makes the angle of 45° at the centre?Solution
Radius = AO = BO = 7 cm Length of arc AB = Circumference of circle × (angle of sector)/360 = 2πr × (45°)/(360°) = 2 × 22/7 × 7 × (45°)/(360°) = 5.5 cm Circumference of sector= arc AB + 2 × radius = 5.5 + 7 + 7 = 19.5cm.
More Geometry Questions
(√1157 + 10.15% of 159.89) × 4.85 + 150.25 = ? × 19.67
{(√2305) % of 74.69} × 15.21 - 27.89 × 44.88 + 45.12% of 2399.87
(9116.89 – 8024.89 + 902.95) × 14 = 1800 × ?
(124.99)² = ?
? * 4.89 = (410.15 ÷ 13.97) % of 6190 - 1342.77
181.87 ÷ 13.89 X 8.13 + ? = 11.852Â
(√845 ×19.932+ √4230 ×14.385)/(√1765 ×4.877 ) = ?
180.25 × 14.995 ÷ √26 = ? × 5.985
1224.86% of √6399.98 = (399.99/4.99)% of (? ÷ 6.91 + 39.87)Â
24.11% of 249.99 + √143.97 ÷ 12.02 = ?
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