(I) x2 _6x = 7 (II) 2y2 + 13y + 15 = 0
I. x2- 6x = 7 or x2- 6x - 7 = 0 ( x – 7) (x -1) = 0, or x = 7, II. 2y2+ 13y + 15 = 0, or 2y2+ 3y + 10y + 15 = 0 y(2y + 3) +5 (2y + 3) = 0, or (2y + 3) (y + 5) = 0 y = -3/2 , -5 Hence, x >y
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