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    Question

    (I) x2 _ 6x = 7 (II) 2y2 + 13y +

    15 = 0 In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if;
    A x < y Correct Answer Incorrect Answer
    B x > y Correct Answer Incorrect Answer
    C x=y Correct Answer Incorrect Answer
    D x≥y Correct Answer Incorrect Answer
    E x≤y Correct Answer Incorrect Answer

    Solution

    I. x2 - 6x = 7 or x2 - 6x - 7 = 0 ( x – 7) (x -1) = 0, or x = 7, II. 2y2 + 13y + 15 = 0 , or 2y2 + 3y + 10y + 15 = 0 y(2y + 3) +5 (2y + 3) = 0, or (2y + 3) (y + 5) = 0 y = -3/2 , -5 Hence, x >y

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