Question
The value of the expression (1 + sec22° + cot68°)(1
– cosec22° + tan68°) isSolution
(1 + sec 22° + cot 68°)(1 − cosec 22° + tan 68°) (1 + sec 22° + cot 68°)(1 − cosec 22° + tan 68°) (1 + 1/cos22° + (sin 22° / cos22°) )(1 – (1/sin22°) + (cos22° / sin22°)) ((1+cos 22° +sin 22°) / (cos22°)) ((cos22° +sin 22° −1) / (sin22°)) (sin2 22° + cos2 22° + 2cos22° × sin22° −1) / (cos22° sin22°) (1+2cos22° sin22° −1) / (cos22° sin22°) = 2
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