Question
If a + b + c = 0 then the value of (1/(a+b)(b+c)) +
(1/(b+c)(c+a)) + (1/(c+a)(a+b)) isSolution
If a + b + c = 0 that means a + b = - c b + c = - a a + C = -b (1 / (a+b)(b+c)) + (1 / (b+c)(c+a)) + (1 / (c+a)(a+b)) Now put the value of equation 1, 2, 3 we get => 1 / (-c × -a) + 1 / (-a × -b) + 1 / (-b × -c) => (1 / ac) + (1 / ab) + (1 / bc) = (b + c + a) / (abc) Also we know that a + b + c = 0 So => (0 / abc) = 0
In 16-bit 2’s complement representation, the decimal number -28 is
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