Question
If x2 + y2 + 2x + 1 = 0, therefore
the value of x31 + y35 isSolution
x2 + y2 + 2x + 1 = 0 x2 + 2x + 1 + y2 = 0 {∵ (x + 1) 2 = x2 + 2x + 1} (x + 1)2 + y2 = 0 there4; (x + 1) 2 = 0, y2 = 0 x+1 = 0 y = 0 x = -1 y = 0 x31 + y35 minus;131 + 035 = -1
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