📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!

    âš¡ Month End Offer - Flat 52% Off On All Courses! Enroll Now âš¡
    00:00:00 AM Left

    Question

    Find the largest number that divides 400, 500, and 600,

    leaving remainders 10, 20, and 30 respectively.
    A 90 Correct Answer Incorrect Answer
    B 30 Correct Answer Incorrect Answer
    C 110 Correct Answer Incorrect Answer
    D 130 Correct Answer Incorrect Answer

    Solution

    Let the required number be x. When dividing 400 by x, the remainder is 10, so 400 - 10 = 390 is divisible by x. When dividing 500 by x, the remainder is 20, so 500 - 20 = 480 is divisible by x. When dividing 600 by x, the remainder is 30, so 600 - 30 = 570 is divisible by x. Now, we need to find the greatest common divisor (GCD) of 390, 480, and 570. Prime factorizations: 390 = 2 * 3 * 5 * 13 480 = 2^5 * 3 * 5 570 = 2 * 3 * 5 * 19 The GCD is 2 * 3 * 5 = 30. Therefore, the required number is 30.

    Practice Next
    More Divisibility rules Questions
    ask-question