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    Question

    What is the least number which when divided by 15, 18

    and 36 leaves the same remainder 9 in each case and is divisible by 11?
    A 1269 Correct Answer Incorrect Answer
    B 1089 Correct Answer Incorrect Answer
    C 1080 Correct Answer Incorrect Answer
    D 1071 Correct Answer Incorrect Answer

    Solution

    Take LCM of 15, 18, 36 = 180 The required number which is exactly divisible by 11. ⇒ 180x + 9 Put x = 6 ⇒ 180 × 6 + 9 ⇒ 1089 is divisible by 11.

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