Question
What is the least number which when divided by 15, 18
and 36 leaves the same remainder 9 in each case and is divisible by 11?Solution
Take LCM of 15, 18, 36 = 180 The required number which is exactly divisible by 11. ⇒ 180x + 9 Put x = 6 ⇒ 180 × 6 + 9 ⇒ 1089 is divisible by 11.
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