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Runs scored by 4’s = 22 × 4 = 88 ………………(i) by 6’s = 6 × 6 = 36 ………………..(ii) Total runs by 4’s and 6’s = 88 + 36 = 124 remaining runs = 161 - 124 = 37 By taking 1’s and 2’s he has scored these 37 runs. To minimize the number of balls Rahane has to score more runs taking 2’s. So he can score 36 runs by taking 2’s and 1 by taking a 1. So balls for 1’s and 2’s = 18 + 1 = 19 ……………….(iii) So total balls (minimum) = 22 + 6 + 19 = 47
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