Question
Study the given graph and answer the question that
follows. Revenue and Expenditure (In ₹ Crores) of a company XYZ from 2014-19 In how many years was the profit (Revenue-Expenditure) as a percentage of the revenue, more than 25%?Solution
Profit of company in 2014 = Rs.(150 – 130) cr ⇒ Profit of company in 2014 = Rs. 20 cr Percentage Revenue = Profit/Revenue × 100 Percentage Revenue of company in 2014 = 20/150 × 100 = 13.33% ----(1) Profit of company in 2015 = Rs.(210 – 150) cr ⇒ Profit of company in 2015 = Rs. 60 cr Percentage Revenue of company in 2015 = 60/210 × 100 = 28.57% ----(2) Profit of company in 2016 = Rs.(200 – 175) cr ⇒ Profit of company in 2016 = Rs. 25 cr Percentage Revenue of company in 2016 = 25/200 × 100 = 12.5% ----(3) Profit of company in 2017 = Rs.(240 – 200) cr ⇒ Profit of company in 2017 = Rs. 40 cr Percentage Revenue of company in 2017 = 40/240 × 100 = 16.67% ----(4) Profit of company in 2018 = Rs.(220 – 165) cr ⇒ Profit of company in 2018 = Rs. 55 cr Percentage Revenue of company in 2018 = 55/220 × 100 = 25% ----(5) Profit of company in 2019 = Rs.(255 – 170) cr ⇒ Profit of company in 2019 = Rs. 85 cr Percentage Revenue of company in 2019 = 85/255 × 100 = 33.33% ----(6) We observe that only (2) and (6) have profit more than 25% ⇒ Number of years in which profit is more than 25% = 2
1219.98 ÷ 30.48 × 15.12 = ? × 2.16
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
`1804/898-:99/699xx749/751=?`
(√845 ×19.932+ √4230 ×14.385)/(√1765 ×4.877 ) = ?
Direction: Please solve the following expression and choose the closest option
`(13.022)^(2)+ (42.93)^(2)-(53.125)^(2)+(192.33xx14.88)=?- (88.44)^(2)- (42.03 xx 23.12)`
√49 + 6.66% of 1725 + 22² = ?² - √361
What approximate value will replace the question mark (?) in the following?
? =...
? = 49.97% of 38.09% of 1998.95
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)