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Let the efficiency of 'K' = 7x units/day
Then, efficiency of 'L' = 7x X (5/7) = 5x units/day
Statement I:
5 X work done by 'K' = 7 X work done by 'L'
Or, 5 X 7x = 7 X 5x
Or, 35x = 35x
So, data in statement I alone is not sufficient to answer the question.
Statement II:
Time taken by 'K' to complete the whole work alone:
= (2x + 3) 2 X {100 ÷ (4x 2 + 18x + 3 2 - 6x) }
= (2x + 3) 2 X {100 ÷ (4x 2 + 12x + 9) }
= (2x + 3) 2 X {100 ÷ (2x + 3) 2 } = 100 days
So, total work = 100 X 7x = 700x units
So, time taken by K and L together to complete the work:
= 700x ÷ (5x + 7x)
= 700x ÷ 12x = 58(1/3) days
So, data in statement II alone is sufficient to answer the question.
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