Question
A boat takes half time in moving a certain distance
downstream than upstream. The ratio of the speed of the boat in still water and that of the current is :Solution
Downstream speed = x + y Upstream speed = x – y Speed = Distance/Time => x  + y = D/T  ------ (i) => x - y = D/2T  ------ (ii) On solving (i) and (ii) we will get, => x = 3D/4T => y = D/4T => x/y = (3D/4T) × (4T/D) = 3∶ 1
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